(x^2+2x-5)-(3x+2)=x^2-1

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Solution for (x^2+2x-5)-(3x+2)=x^2-1 equation:


Simplifying
(x2 + 2x + -5) + -1(3x + 2) = x2 + -1

Reorder the terms:
(-5 + 2x + x2) + -1(3x + 2) = x2 + -1

Remove parenthesis around (-5 + 2x + x2)
-5 + 2x + x2 + -1(3x + 2) = x2 + -1

Reorder the terms:
-5 + 2x + x2 + -1(2 + 3x) = x2 + -1
-5 + 2x + x2 + (2 * -1 + 3x * -1) = x2 + -1
-5 + 2x + x2 + (-2 + -3x) = x2 + -1

Reorder the terms:
-5 + -2 + 2x + -3x + x2 = x2 + -1

Combine like terms: -5 + -2 = -7
-7 + 2x + -3x + x2 = x2 + -1

Combine like terms: 2x + -3x = -1x
-7 + -1x + x2 = x2 + -1

Reorder the terms:
-7 + -1x + x2 = -1 + x2

Add '-1x2' to each side of the equation.
-7 + -1x + x2 + -1x2 = -1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-7 + -1x + 0 = -1 + x2 + -1x2
-7 + -1x = -1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-7 + -1x = -1 + 0
-7 + -1x = -1

Solving
-7 + -1x = -1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -1x = -1 + 7

Combine like terms: -7 + 7 = 0
0 + -1x = -1 + 7
-1x = -1 + 7

Combine like terms: -1 + 7 = 6
-1x = 6

Divide each side by '-1'.
x = -6

Simplifying
x = -6

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